Microsoft 70-544 Value Pack (Frequently Bought Together)

You need to draw a straight red line between the start and end points of a calculated route.
Which code segment should you use?

• A. var locationArray = new Array(); var len = route.Itinerary.Segments.length; locationArray.push(route.Itinerary.Segments[0].LatLong);
  locationArray.push(route.Itinerary.Segments[len].LatLong); shape = new
  VEShape(VEShapeType.Polyline, locationArray); shape.SetLineColor(new VEColor(255, 0,
  0, 0)); shape.HideIcon(); layer.AddShape(shape);
• B. var locationArray = new Array(); var len = route.Itinerary.Segments.length; locationArray.push(route.Itinerary.Segments[1].LatLong);
  locationArray.push(route.Itinerary.Segments[len].LatLong); shape = new
  VEShape(VEShapeType.Pushpin, locationArray); shape.SetLineColor(new VEColor(255,
  0, 0, 0.5)); layer.AddShape(shape);
• C. var locationArray = new Array(); var len = route.Itinerary.Segments.length; locationArray.push(route.Itinerary.Segments[0].LatLong);
  locationArray.push(route.Itinerary.Segments[len-1].LatLong); shape = new
  VEShape(VEShapeType.Polyline, locationArray); shape.SetLineColor(new VEColor(255, 0,
  0, 0.5)); shape.HideIcon(); layer.AddShape(shape);
• D. var locationArray = new Array(); var len = route.Itinerary.Segments.length; locationArray.push(route.Itinerary.Segments[0].LatLong);
  locationArray.push(route.Itinerary.Segments[len-1].LatLong); shape = new
  VEShape(VEShapeType.Polyline, locationArray); shape.SetLineColor(new VEColor(255, 0,
  0, 0)); layer.AddShape(shape);

You need to display a polyline on a new user-defined shape layer. Which two actions should you perform? (Each correct answer presents part of the solution. Choose two.)

• A. Add a new polyline to the map by using the VEMap.AddPolyline method.
• B. Create a shape of type VEShapeType.Polyline and add it to the map by using the
  VEMap.AddShape method.
• C. Create a new shape layer and add it to the map by using the VEMap.AddShapeLayer method.
• D. Create a shape of type VEShapeType.Polyline and add it to the shape layer by using the VEShapeLayer.AddShape method.

Your company plans to implement a store locator on its Web site. You need to center a
Virtual Earth 6.0 map on a selected store location. What are two possible methods you can use to achieve this goal? (Each correct answer presents a complete solution. Choose two.)

• A. VEMap.SetCenterAndZoom
• B. VEMap.PanToLatLong
• C. VEMap.SetMapMode
• D. VEMap.SetPitch
• E. VEMap.StartContinousPan

You are integrating third-party data into a Virtual Earth 6.0 application. The data that is retrieved from the third party is stored in an array named Results. The Results array is stored inside a Web handler. The data is stored in the following format.
Results(0).Add("name", "Mike Pizzaria") Results(0).Add("address", "123 Main St., New
York, NY") Results(0).Add("latitude", "40.123") Results(0).Add("longitude", "-70.456")
Results(0).Add("thumbnail", "http://www.site.com/st3465.jpg") ... Return Results The Web handler uses the GeoRSSFeed class to accept items of type GeoRSSItem. The class contains the ToString() method that writes the GeoRSS feed to a string. The Web handler
GeoRSS integration is defined by the following code segment. (Line numbers are included for reference only.) 01 Dim feed As New GeoRSSFeed() 02 Dim curItem As GeoRSSItem
03 For i As Integer = 0 To Results.Count - 1 04 curItem = New GeoRSSItem() 05 ... 06 feed.Add(curItem) 07 Next 08 // Write feed to HTTP Response 09
context.Write(feed.ToString()); The Web handler uses the GeoRSSItem class that contains the following code segment. (Line numbers are included for reference only.) 10
Public Class GeoRSSItem 11 Public elements As Dictionary(Of String, String) 12 Public
Sub New() 13 elements = New Dictionary(Of String, String)() 14 End Sub 15 Public Sub
Add(ByVal pName As String, _ ByVal pValue As String) 16 elements.Add(pName, pValue)
17 End Sub 18 Public Overloads Overrides Function ToString() As String 19 Dim returnValue As New StringBuilder() 20 For Each key As String In elements.Keys 21 returnValue.AppendFormat("" & Chr(9) & "" & _ Chr(9) & "<{0}>{1}</{0}>" & Chr(10) & "", _ key, elements(key)) 22 Next 23 Return returnValue.ToString() 24 End Function 25 End
Class You need to encode the data inside the Results array into the GeoRSS format.
Which code segment should you insert at line 05?

• A. Dim objEnumerator As IEnumerator Dim Keys As Collections.Generic.Dictionary(Of
  String, _ String).KeyCollection = Results(i).Keys() Dim curKey As String objEnumerator =
  Keys.GetEnumerator() Do While objEnumerator.MoveNext curKey =
  objEnumerator.Current curItem.Add(curKey, Results(i)(curKey)) Loop
• B. curItem.Add("title", Results(i)("name")) curItem.Add("description",
  String.Format("{0}|{1}", _ Results(i)("address"), Results(i)("thumbnail"))) curItem.Add("latitude", Results(i)("latitude")) curItem.Add("longitude",
  Results(i)("longitude"))
• C. curItem.Add("name", Results(i)("name")) curItem.Add("address", string.Format("{0}|{1}",
  _ Results(i)("address"), Results(i)("thumbnail")) curItem.Add("latitude",
  Results(i)("latitude")) curItem.Add("longitude", Results(i)("longitude"))
• D. curItem.Add("title", Results(i)("name")) curItem.Add("description", Results(i)("address")) curItem.Add("latitude", Results(i)("latitude")) curItem.Add("longitude",
  Results(i)("longitude")) curItem.Add("icon", Results(i)("thumbnail"))

You are creating a Web application. You are given the URL of a Web page. When the URL is encoded with map control properties, it generates custom maps by using the Virtual
Earth 6.0 map control.
The Web page uses the following JavaScript code segment to decode the URL.
var pos=location.search.indexOf("?") +1;
var loc1=location.search.substr(pos);
var point1=loc1.split(" & ");
var a= point1[0];
var b= point1[1];
var c= point1[2];
var d=point1[3];
var e= point1[4];
var f= point1[5];
var g= point1[6];
map=new VEMap('myMap');
map.LoadMap(new VELatLong(a,b),c,d,e,f,g);
You need to encode the URL to generate a custom map by using your own settings.
Which encoded URL should you use?

• A. http: //www.mymappingsite.com/mymappage.aspx?a=40.689167&-
  b=74.04472&c=21&d=o&e=0&f=2&g=0
• B. http: //www.mymappingsite.com/mymappage.aspx?40.689167&-74.04472&0&h&1&6&1
• C. http: //www.mymappingsite.com/mymappage.aspx?40.689167&-
  7 4.04472&1&a%&0&14&0
• D. http: //www.mymappingsite.com/mymappage.aspx?40.689167&-
  7 4.04472&12&r&0&2&1